Optimal. Leaf size=187 \[ -\frac{(b c-a d)^2 (a d+5 b c) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{16 b^{3/2} d^{7/2}}-\frac{\left (a+b x^2\right )^{3/2} \sqrt{c+d x^2} (a d+5 b c)}{24 b d^2}+\frac{\sqrt{a+b x^2} \sqrt{c+d x^2} (b c-a d) (a d+5 b c)}{16 b d^3}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d} \]
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Rubi [A] time = 0.171749, antiderivative size = 187, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {446, 80, 50, 63, 217, 206} \[ -\frac{(b c-a d)^2 (a d+5 b c) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{16 b^{3/2} d^{7/2}}-\frac{\left (a+b x^2\right )^{3/2} \sqrt{c+d x^2} (a d+5 b c)}{24 b d^2}+\frac{\sqrt{a+b x^2} \sqrt{c+d x^2} (b c-a d) (a d+5 b c)}{16 b d^3}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d} \]
Antiderivative was successfully verified.
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Rule 446
Rule 80
Rule 50
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^3 \left (a+b x^2\right )^{3/2}}{\sqrt{c+d x^2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x (a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^2\right )\\ &=\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}-\frac{(5 b c+a d) \operatorname{Subst}\left (\int \frac{(a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^2\right )}{12 b d}\\ &=-\frac{(5 b c+a d) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{24 b d^2}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}+\frac{((b c-a d) (5 b c+a d)) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x}}{\sqrt{c+d x}} \, dx,x,x^2\right )}{16 b d^2}\\ &=\frac{(b c-a d) (5 b c+a d) \sqrt{a+b x^2} \sqrt{c+d x^2}}{16 b d^3}-\frac{(5 b c+a d) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{24 b d^2}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}-\frac{\left ((b c-a d)^2 (5 b c+a d)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx,x,x^2\right )}{32 b d^3}\\ &=\frac{(b c-a d) (5 b c+a d) \sqrt{a+b x^2} \sqrt{c+d x^2}}{16 b d^3}-\frac{(5 b c+a d) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{24 b d^2}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}-\frac{\left ((b c-a d)^2 (5 b c+a d)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x^2}\right )}{16 b^2 d^3}\\ &=\frac{(b c-a d) (5 b c+a d) \sqrt{a+b x^2} \sqrt{c+d x^2}}{16 b d^3}-\frac{(5 b c+a d) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{24 b d^2}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}-\frac{\left ((b c-a d)^2 (5 b c+a d)\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x^2}}{\sqrt{c+d x^2}}\right )}{16 b^2 d^3}\\ &=\frac{(b c-a d) (5 b c+a d) \sqrt{a+b x^2} \sqrt{c+d x^2}}{16 b d^3}-\frac{(5 b c+a d) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{24 b d^2}+\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{6 b d}-\frac{(b c-a d)^2 (5 b c+a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{16 b^{3/2} d^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.422248, size = 173, normalized size = 0.93 \[ \frac{b \sqrt{d} \sqrt{a+b x^2} \left (c+d x^2\right ) \left (3 a^2 d^2+2 a b d \left (7 d x^2-11 c\right )+b^2 \left (15 c^2-10 c d x^2+8 d^2 x^4\right )\right )-3 (b c-a d)^{5/2} (a d+5 b c) \sqrt{\frac{b \left (c+d x^2\right )}{b c-a d}} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b c-a d}}\right )}{48 b^2 d^{7/2} \sqrt{c+d x^2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.017, size = 532, normalized size = 2.8 \begin{align*} -{\frac{1}{96\,b{d}^{3}}\sqrt{b{x}^{2}+a}\sqrt{d{x}^{2}+c} \left ( -16\,{x}^{4}{b}^{2}{d}^{2}\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}-28\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{x}^{2}ab{d}^{2}\sqrt{bd}+20\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{x}^{2}c{b}^{2}d\sqrt{bd}+3\,{d}^{3}\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){a}^{3}+9\,\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){a}^{2}cb{d}^{2}-27\,\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){c}^{2}a{b}^{2}d+15\,{b}^{3}\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){c}^{3}-6\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{a}^{2}{d}^{2}\sqrt{bd}+44\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}acbd\sqrt{bd}-30\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{c}^{2}{b}^{2}\sqrt{bd} \right ){\frac{1}{\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}}}{\frac{1}{\sqrt{bd}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.06232, size = 972, normalized size = 5.2 \begin{align*} \left [\frac{3 \,{\left (5 \, b^{3} c^{3} - 9 \, a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} + a^{3} d^{3}\right )} \sqrt{b d} \log \left (8 \, b^{2} d^{2} x^{4} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x^{2} - 4 \,{\left (2 \, b d x^{2} + b c + a d\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c} \sqrt{b d}\right ) + 4 \,{\left (8 \, b^{3} d^{3} x^{4} + 15 \, b^{3} c^{2} d - 22 \, a b^{2} c d^{2} + 3 \, a^{2} b d^{3} - 2 \,{\left (5 \, b^{3} c d^{2} - 7 \, a b^{2} d^{3}\right )} x^{2}\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c}}{192 \, b^{2} d^{4}}, \frac{3 \,{\left (5 \, b^{3} c^{3} - 9 \, a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} + a^{3} d^{3}\right )} \sqrt{-b d} \arctan \left (\frac{{\left (2 \, b d x^{2} + b c + a d\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c} \sqrt{-b d}}{2 \,{\left (b^{2} d^{2} x^{4} + a b c d +{\left (b^{2} c d + a b d^{2}\right )} x^{2}\right )}}\right ) + 2 \,{\left (8 \, b^{3} d^{3} x^{4} + 15 \, b^{3} c^{2} d - 22 \, a b^{2} c d^{2} + 3 \, a^{2} b d^{3} - 2 \,{\left (5 \, b^{3} c d^{2} - 7 \, a b^{2} d^{3}\right )} x^{2}\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c}}{96 \, b^{2} d^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{3} \left (a + b x^{2}\right )^{\frac{3}{2}}}{\sqrt{c + d x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.25854, size = 293, normalized size = 1.57 \begin{align*} \frac{\sqrt{b^{2} c +{\left (b x^{2} + a\right )} b d - a b d} \sqrt{b x^{2} + a}{\left (2 \,{\left (b x^{2} + a\right )}{\left (\frac{4 \,{\left (b x^{2} + a\right )}}{b d} - \frac{5 \, b^{2} c d^{3} + a b d^{4}}{b^{2} d^{5}}\right )} + \frac{3 \,{\left (5 \, b^{3} c^{2} d^{2} - 4 \, a b^{2} c d^{3} - a^{2} b d^{4}\right )}}{b^{2} d^{5}}\right )} + \frac{3 \,{\left (5 \, b^{3} c^{3} - 9 \, a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} + a^{3} d^{3}\right )} \log \left ({\left | -\sqrt{b x^{2} + a} \sqrt{b d} + \sqrt{b^{2} c +{\left (b x^{2} + a\right )} b d - a b d} \right |}\right )}{\sqrt{b d} d^{3}}}{48 \,{\left | b \right |}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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